prove that 3+root 2 is an irrational number
Answers
Answered by
1
Answer:
3+root 2 is irrational number
Step-by-step explanation:
Let 3+root2=x/y
where x and y are integers and y not equal to 0....
3+root 2=x/y
root 2 =x/y-3
root 2= (3y-x) /y
therefore, root 2=(3y-x) /y Is rational as x, y and 3 are integers. But this contradicts the fact that root 2 is irrational....
so, it concludes that 3+root 2 is irrational...
hence proved.....
Answered by
19
Answer:
3+ root 2 is an irrational number
hope it helped you
Similar questions