Question

prove that 3+root 2 is an irrational number ​

Answer 1

Answer:

3+root 2 is irrational number

Step-by-step explanation:

Let 3+root2=x/y

where x and y are integers and y not equal to 0....

3+root 2=x/y

root 2 =x/y-3

root 2= (3y-x) /y

therefore, root 2=(3y-x) /y Is rational as x, y and 3 are integers. But this contradicts the fact that root 2 is irrational....

so, it concludes that 3+root 2 is irrational...

hence proved.....

Answer 2

Answer:

3+ root 2 is an irrational number

hope it helped you