Question

prove that 3 root 2 is irrational number

Answer 1

this is your answer...

Answer 2

Hey !

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3√2 is irrational

Let us consider in contradiction that 3√2 is rational.

Let us consider 3√2 =a/b where a and b are co primes.

3√2 = a/b

√2 = a/b - 3

√2 = a - 3b/ b

√2 = integer - 3( integer ) / integer

√2 = integer / integer { form in p/q }

We know that a number which is in the form of p/q is rational number.

So , 3√2 is rational.

But we know that √2 is irrational .

So, 3√2 is irrational number

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