Prove that (3 - root 7)2 is an irrational number.
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(3-√7)^2=(3-√7)(3-√7)
(3×3-3×√7-3×√7+√7×√7)
(9-3√7-3√7+7)
(16-6√7)
So,(3-√7)^2is an irrational number
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