prove that (3- root 7)power 2 ia a irrational no
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[3-root7]power2
by using [a-b]power 2 identity
9-7+6root7
2+6root7
let 2+6root7=rational
2+6root7=p/q
2=p/q-6root7\
2q/p=-6root7
2q/-6p=root7
1q/-3p=root7
since root 7 is irrational
then 1q/-3p is also irrational
therefore 2+6root7 is irrational
by using [a-b]power 2 identity
9-7+6root7
2+6root7
let 2+6root7=rational
2+6root7=p/q
2=p/q-6root7\
2q/p=-6root7
2q/-6p=root7
1q/-3p=root7
since root 7 is irrational
then 1q/-3p is also irrational
therefore 2+6root7 is irrational
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