Question

prove that 3V10 is an irrational number.​

Answer 1

Answer:

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Step-by-step explanation:

Let's assume 3+5 is a rational number 3+5=ba

Let's assume 3+5 is a rational number 3+5=ba5=ba−3

Let's assume 3+5 is a rational number 3+5=ba5=ba−35=ba−b3b

Let's assume 3+5 is a rational number 3+5=ba5=ba−35=ba−b3b5=ba−3b

Let's assume 3+5 is a rational number 3+5=ba5=ba−35=ba−b3b5=ba−3bAs we know that 5 is an irrational number. 

Let's assume 3+5 is a rational number 3+5=ba5=ba−35=ba−b3b5=ba−3bAs we know that 5 is an irrational number. so, ba−3b is also an irrational number. 

Let's assume 3+5 is a rational number 3+5=ba5=ba−35=ba−b3b5=ba−3bAs we know that 5 is an irrational number. so, ba−3b is also an irrational number. Therefore, our assumption is wrong.

Let's assume 3+5 is a rational number 3+5=ba5=ba−35=ba−b3b5=ba−3bAs we know that 5 is an irrational number. so, ba−3b is also an irrational number. Therefore, our assumption is wrong.Hence, 3+5 is an irrational number