prove that(4+3^-20)1/2+(4-3^-20) 1/2 =6
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Step-by-step explanation:
4+3−20−−−−√=4+320−−√i=4+65–√i=(9−5)+2.3.5–√i
=32+2.3.5–√i++(5–√i)2=(3+5–√i)2
⟹(4+3−20−−−−√)12=3+5–√i
Similarly, (4−3−20−−−−√)12=3−5–√i
Therefore, (4+3−20−−−−√)12+(4−3−20−−−−√)12=3+5–√i+3−5–√i=6
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