Question

Prove that 4 digit palindrome is always divisible by 11​

Answer 1

Answer:

Step-by-step explanation:

Let a be the one’s digit and b be the tenth’s digit. Then hundred’s and thousand’s digit will be b and a respectively

Then the number will be

1000a+100b+10b+a

=1001a +110b

=11(91a+10b)

So the number is divisible by 11