prove that 4 minus 5 root 2 is an irrational number
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Consider, 4−3√2
Let 4−3√2 = (a/b) a rational number
⇒ −3√2 = (a/b) − 4
⇒ −3√2 = (a − 4b)/b
⇒ √2 = (a − 4b)/(−3b)
Since a, b are integers, then (a − 4b)/(−3b) represents a rational number.
But this is a contradiction since RHS is a rational number where as LHS (√2) is an irrational number
Hence our assumption that " 4−3√2 = (a/b) is a rational number" is incorrect.
Thus 4−3√2 is an irrational number.
hope it will help u...
Let 4−3√2 = (a/b) a rational number
⇒ −3√2 = (a/b) − 4
⇒ −3√2 = (a − 4b)/b
⇒ √2 = (a − 4b)/(−3b)
Since a, b are integers, then (a − 4b)/(−3b) represents a rational number.
But this is a contradiction since RHS is a rational number where as LHS (√2) is an irrational number
Hence our assumption that " 4−3√2 = (a/b) is a rational number" is incorrect.
Thus 4−3√2 is an irrational number.
hope it will help u...
Answered by
1
Answer:
Let (4-5√2) be a rational number
then,there exist co prime a and b such that
(4-5√2)= a/b
5√2= a-4b/b
√2= a-4b/5b
since a and b are integers so a-4b/5b is rational
thus √2 is also rational but this contradict the fact that √2 is irrational. so our assumption is incorrect
Hence ,(4-5√2) is irrational
if there is any mistake in my solution kindly mention in comments and I hope it will help you
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