Prove that 4^n-3n-1 is a multiple of 9 for every n belongs N
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Yes, It is true. 4^n-3n-1 is a multiple of 9
If we put n=1,then
4^1-3(1)-1=0
and 0 is a multiple of 9
If we put n=2,then
4^2-3(2)-1=9
and 9 is a multiple of 9
Hence proved.
If we put n=1,then
4^1-3(1)-1=0
and 0 is a multiple of 9
If we put n=2,then
4^2-3(2)-1=9
and 9 is a multiple of 9
Hence proved.
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2
Hello!
I will be proving this by Principle of Mathematical Induction which is the proper way to do in these questions to get marks in schools.Here is my working..
Regards.
I will be proving this by Principle of Mathematical Induction which is the proper way to do in these questions to get marks in schools.Here is my working..
Regards.
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