Question

Prove that 4(sin^230°+cos^260°)-3(cos^245°)=7/2

Answer 1

Answer:

I think your question is wrong maybe.

Step-by-step explanation:

= 4(Sin²30° + Cos²60°) - 3Cos²45°

Substituting the values of Sin30° = [texfrac{1}{2}[/tex] ]\= Cos60° , Cos45° = [texfrac{1}{2}[/tex] ]\

We get

4 - $\frac{3}{2}$ = $\frac{5}{2}$