prove that 4( 30° + 60°) - 3 ( 45° - 90°) = 2
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prove that 4( 30° + 60°) - 3 ( 45° - 90°) = 2
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It is given that,
4(sin⁴30°+cos⁴60°)-3(cos²45°-sin²90°)
4((1/2)⁴+(1/2)⁴)-3((1/√2)²-1)
4(1/16+1/16)-3(1/2-1)
4(2/16)-3(-1/2)
4(1/8)+3/2
1/2+3/2=4/2=2
Hope it helps....
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