prove that :- (4ax+3y)^2-(4ax-3y)^2
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Answer:
(4ax+3y)²-(4ax-3y)²
=[4ax+3y+(4ax-3y)][4ax+3y-(4ax-3y)]
=(4ax+3y+4ax-3y)(4ax+3y-4ax+3y)
=8ax × 9y
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