prove that 5 + 2 √3 is an irrational number
Answers
Answer:
Let assume that 5 +2 √3 be a rational number
5 + 2√3 = a /b {where a and b are co-prime}
2√3 = a / b + 5
√3 =(a + 5b)/2b
since a/ b is a rational no.
therefore ( a +5b)/2 b js also rational no.
therefore √3 is also rational
since it contradicts the fact that √3 is irrational
therefore our assumption is wrong
therefore 5 + 2√3 is an irrational number
Hence proved!!!!!
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Answer:
Step-by-step explanation:
Let us assume that 5+2√3 is a rational number which can be expressed in the form p/q where p and q are rational numbers and q≠0
∴ 5+2√3 = p/q
2√3 = p/q - 5
2√3 = p-5q/q
√3 = p-5q/2q
On squaring both sides,
3 = p² + 25q² - 10pq/4q²
From this,
3 is a factor of p² +25q² +10pq/4q²
∴√3 is a factor of p/q
∴√3 is a rational number.
But this contradicts the fact that √3 is an irrational number.
Therefore, our assumption is wrong
∴5+2√3 is an irrational number
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