prove that √5 +√2 is irrational
Answers
Answered by
1
Hi Friend !!!
Here is ur answer !!!
Let's assume that √5+√2 is a rational number
√5+√2 = p/q
√5 = p/q - √2
squaring on both sides
5 = p²/q² - 2(p/q)(√2) + 2
5-2 = p²/q²- 2p/q √2
p²/q² -3 = 2p/q √2
p²-3q²/q² (q/2p) = √2
p²-3q²/2pq = √2
if p, q are integers then p²-3q²/2pq is a rational number
Then √2 also a rational number
But it contradicts the fact that √2 is irrational number
So our assumption is wrong
√5 + √2 is an irrational number
Hope it helps u : )
Here is ur answer !!!
Let's assume that √5+√2 is a rational number
√5+√2 = p/q
√5 = p/q - √2
squaring on both sides
5 = p²/q² - 2(p/q)(√2) + 2
5-2 = p²/q²- 2p/q √2
p²/q² -3 = 2p/q √2
p²-3q²/q² (q/2p) = √2
p²-3q²/2pq = √2
if p, q are integers then p²-3q²/2pq is a rational number
Then √2 also a rational number
But it contradicts the fact that √2 is irrational number
So our assumption is wrong
√5 + √2 is an irrational number
Hope it helps u : )
Similar questions