Prove that 5 √3-4 is irrational.
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Let 4-5√3 be a rational number.
4-5√3= a/b where a and b are co primes
-5√3=a/b-4
-5√3=a-4b/b
a-4b/b+5=√3
But this contradiction is wrong therefore 4-5√3 is a irrational number.
Hope this will help you.
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