Question

Prove that 5-3/7 root 3

Answer 1

Step-by-step explanation:

let it be a rational number

5 - \frac{3}{7} \sqrt{3} = \frac{a}{b}5−

7

3

3

=

b

a

= > - \frac{3}{7} \sqrt{3 } = \frac{a}{b} - 5=>−

7

3

3

=

b

a

−5

= > \frac{3}{7} \sqrt{3} = \frac{5b - a}{b}=>

7

3

3

=

b

5b−a

\sqrt{3} = \frac{7(5b - a)}{3b}

3

=

3b

7(5b−a)

it seems that √3 is rational

so our assumption get wrong because √3 is irrational number so 5-3/7√3 is irrational