Question

prove that 5√3 is irrational​

Answer 1

Step-by-step explanation:

Let us assume the given number be rational and we will write the given number in p/q form

$= > 5 - \sqrt{3} = \frac{p}{q} \\ = > \sqrt{3} = \frac{5q - p}{q}$

We observe that LHS is irrational and RHS is rational, which is not possible.

This is contradiction.

Hence our assumption that given number is rational is false

⇒5-√3 is irrational .