Prove that √5+√3 n rational number
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Step-by-step explanation:
First prove that sqrt(3) is irrational.
This is done by contradiction.
Let sqrt(3) be rational. sqrt(3) = p/q where p/q is irreducible fraction (otherwise we reduce it).
3=p^2/q^2
3q^2=p^2
So p^2 is divisible by 3, hence p is divisible by 3. Let p=3n
3q^2 = (3n)^2
3q^2 = 9n^2
q^2 = 3n^2
So, q^2 is divisible by 3, hence q is divisible by 3.
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