Math, asked by maths7860, 1 year ago

Prove that √5 is irrational


IndieLov: it is irrational but you can show it like this: √5 (2φ-1)^2

Answers

Answered by syedaleemuddin
4
Let us assume that √5 is a rational number.
we know that the rational numbers are in the form of p/q form where p,q are intezers.
so, √5 = p/q
     p = √5q
we know that 'p' is a rational number. so √5 q must be rational since it equals to p
but it doesnt occurs with √5 since its not an intezer
therefore, p =/= √5q
this contradicts the fact that √5 is an irrational number
hence our assumption is wrong and √5 is an irrational number.

IndieLov: it's "integer" not "intezer"
syedaleemuddin: it is oky dear
Answered by nikitasharma59
1
 \sqrt{5} is not irrational as is the cannot be expressed in the form p/q where p and q are integers
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