Question

prove that √5 is irratoinal​

Answer 1

Answer:

Here is your answer mate

hope this helps you

Answer 2

Answer:

Hey there,this is ur answer:-

Step-by-step explanation:

let $\sqrt{5}$ be rational

$\sqrt{5}$=a/b (where a and b have no common factor)

($\sqrt{5}$)^2 =(a/b)^2

5=(a/b)^2

5=a^2/b^2

5*b^2=a^2

therefore, a^2 is the multiple of 5

therefore, a is the multiple of 5

let a=5*c

a^2=(5*c)^2

a^2=25*c^2

5*b^2=25*c^2  (5*b^2=a^2)

b^2=(25*c^2)/5

b^2=5*c^2

therefore, b^2 is the multiple of 5

therefore, b is the multiple of 5

a and b have no commom factor, 5

It contradicts that $\sqrt{5$ is not rational, so it is irrational

hope it helps u,

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