prove that 5+root2 is irrational
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we know that root 2 is an irrational so multiple of root 2 also be irrational
and second method is this that you first find root 2 and then × 5 in your copy then you can prove that multiple of root 2 is an irrational number.
Hope it helped!
and second method is this that you first find root 2 and then × 5 in your copy then you can prove that multiple of root 2 is an irrational number.
Hope it helped!
Answered by
14
QUESTION:-
prove that 5+√2 is irrational™
SOLUTION:-
Let 5+√2= Rational
=>5+√2=
[where a & b are co-prime integers they are not [equal to] irrational]
=>5+√2= 
=>√2=
-5
CROSS MULTIPLY RHS↓
√2=
√2=
=>LHS≠RHS[as Irrational≠Rational]
Creates a Contradiction Proving 5+√2 is IRRATIONAL✓
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