Question

Prove that 51+53×80×602÷4=628

Answer 1

Answer:

625.5

Step-by-step explanation:

Given

$51 + 53 \times 80 x 602 \div 4 = 628 \\ \\ we \: have \: to \: prove \: this \: equal \\ \\ take \: l.h.s = 51 + 53 \times 80 x 602 \div 4 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: = 51 + 424 x 150.5 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 628$

Answer 2

$51+53\times 80\times 602\div 4=628$

Step-by-step explanation:

Given:

The equation to verify is:

$51+53\times 80\times 602\div 4=628$

Consider the left hand side of the equation.

$51+53\times 80\times 602\div 4$

Applying BODMAS rule for simplifying the given expression. Here, there is no Bracket or Of sign. So, we will first go with Division followed by Multiplication and then at last Addition.

First, dividing 602 by 4 gives 150.5. So,

$51+53\times 80\times 150.5$

Now, we multiply 50, 80 and 150.5.

$53\times 80=4240\times 150.5=638120$

Now, we add the result to 51, we get

$638120+51=638171$

RHS = 638171

Therefore, LHS = RHS. Hence, proved.