prove that 6 + root2 is irrational
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Answered by
1
Answer:
Since a and b are two integers. Therefore (6-a/b)is a rational number and So root also is a rational number. But it is contradiction to fact root 2 =(6-a/b) is rational number. So we that 6+root 2 is an irrational number.
Answered by
2
Answer:
6+√2 is irrational.
Step-by-step explanation:
Let us assume that 6+√2 is rational.
That is , we can find coprimes a and b (b≠0) such that
Since , a and b are integers , is rational ,and so √2 is rational.
But this contradicts the fact that √2 is irrational.
So, we conclude that 6+√2 is irrational.
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