Question

prove that (7-5√3) is irrational.​

Answer 1

Answer:

We know that root 3 is irrational... So we should take the given no =a/b... Where b not =0 the the given is irrational

Answer 2

Answer:

firstly,

let's √3 is a irrational no

it's possible to 7-5√3 is a rational number

p and q are Integers

7-5√3=p/q. [p is not equal to 0]

5√3=p/q -7 = p- 7 q/q

√3= p - 7q/5

..p and q is a Integers

p - 7q and 2q is also a Integers

now ,

7-5√3 is rational number.

PROVED