Question

prove that 7√5 is irrational​

Answer 1

HEre Is Your Ans ⤵

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➡Let , 7√5 Is an Rational Number

$= > 7 \sqrt{5} = \frac{a}{b} \\ \\ = > \sqrt{5} = \frac{a}{7b} \\ \\ = > irrational \: is \: equal \: to \: rational \: it \: is \: not \: possible$

So , 7√5 Is an Irrational Number

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$<marquee > hope it helps u$

Answer 2

Answer:

Step-by-step explanation:

Let 7 root 5 be rational number then

7 root 5 = p/q where p and q are co prime

Root 5 = p/7q here we consider root 5 is rational but root root is an irrational

So our contradiction is wrong

Hence 7 root 5 is an irrational