Prove that 7+√5 is irrational
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Answered by
5
Let 7√5 be a rational number.
So,
7√5 = p/q.
(p and q are co-prime number and q ≠ 0)
=> √5 = p/7q
As, we can see that p/7q ia rational so √5 should also be rational. But this contradict the fact that √5 is irrational.
So, by this we can say that 7√5 is irrational number.
Answered by
3
Step-by-step explanation:
let us assume that 7+√5 is a rational no.
therefore 7+√5=a\b
√5=a/b-7
hence a rational no. can not be equal to a irrational no.(√5)
therefore 7+√5 is an irrational no.
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