prove that 7√5 is irrational
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Answer:
- Let, 7 root 5 be a rational Number
- Therefore, 7root5 can be expressed in the form of a/b
- Therefore,Root 5 is equal to a/7×b
- Therefore,root 5 is equal to a/7b
- Hence,Root5 Is an Irrational Number
- Therefore a/7b Is also an Irrational Number
- Hence, Proved
- Therefore 7 root 5 is an Irrational Number.
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here is your answer....
Let us assume 7√5 is a rational number.
Then we can find co-prime a and b (b ≠ 0) such that 7√5 = x/y
Rearranging, we get,
√5 = x/7y
Since, x and y are integers, thus, √5 is a rational number, which contradicts the fact that √5 is irrational.
Hence, we can conclude that 7√5 is irrational
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