Math, asked by karuna27678, 6 months ago

prove that 7√5 is irrational​

Answers

Answered by Harsh00055
1

Answer:

  • Let, 7 root 5 be a rational Number
  • Therefore, 7root5 can be expressed in the form of a/b
  • Therefore,Root 5 is equal to a/7×b
  • Therefore,root 5 is equal to a/7b
  • Hence,Root5 Is an Irrational Number
  • Therefore a/7b Is also an Irrational Number
  • Hence, Proved
  • Therefore 7 root 5 is an Irrational Number.

Step-by-step explanation:

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Answered by kanisharchueck
2

hiiiiiiii.....

here is your answer....

Let us assume 7√5 is a rational number.

Then we can find co-prime a and b (b ≠ 0) such that 7√5 = x/y

Rearranging, we get,

√5 = x/7y

Since, x and y are integers, thus, √5 is a rational number, which contradicts the fact that √5 is irrational.

Hence, we can conclude that 7√5 is irrational

hope helps you......

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