prove that 7 root 2 by 5 is irrational number
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Answered by
10
Answer:
Wassup fam
Step-by-step explanation:
let 7√2/5 =a/b (a, b are integers b not equal to zero)
then 7√2=5a/b
so √2=5a/7b
but 5,7,a,b are integers
so √2 is an integer
this is a contradiction
as √2 is irrational
therefore 7√2/5 is irrational
Thor1:
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Answered by
2
Step-by-step explanation:
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