prove that 7-root 5 is irrational given that root 5 is irrational
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Answered by
1
Answer:
we can find co-primes a and b
7-√5=a/b
7/1-a/b=√5
7b-a/b=√5
7b-a/b=√5 is rational,√7 is also rational.this is our contradiction.this contradiction arise due to our wrong assumption.so7-√5 is irrational number
Answered by
0
Answer:
Step-by-step explanation:
let assume (7 - √5) a rational number
∴(7 - √5) = a/b
=> 7 - √5 = a/b
=> √5 = a/b + 7
=> √5 = (a + 7b)/b
as ,here √5 is irrational therefore , whole {(a + 7b)/b} is irrational
∴ 7-√5 is also irrational.
hence proved!
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