Question

p(x) =x^2-4x^2+x+1 then the value of p(0) is​

Answer 1

Answer:

1

Step-by-step explanation:

p(x) =x^2 - 4x^2 + x + 1

p(0) =0^2 - 4(0)^2 + 0 + 1

p(0) =0 - 0 + 0 + 1

p(0) = 1 (Ans)

Answer 2

Answer:

1

Step-by-step explanation:

All you need to do is to put 0 in place of x and you'll get your answer.

p(x) =x^2-4x^2+x+1

p(0)=0^2-4*0^2+0+1

=0-0+0+1

=1

hope It'll be helpful:)