prove that a(2,-1) b(3,4) c(-2,3) d(-3,-2) are vertices of rhombus but not square. also find its area
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AB=√(3-2)²+(4+1)²=√1+25=√26
BC=√(-2-3)²+(3-4)²=√25+1=√26
CD=√(-3+2)²+(-2-3)²=√1+25=√26
AD=√-3-2)²+(-2+1)²=√25+1=√26
Sides is equal
AC=√(-2-2)²+(3+1)²=√16+16=√32
BD=√(-3-3)²+(-2-4)²=√36+36=√72
Diagonals are not equal
Since,sides are equal but diagonals are not equal therefore it is rhombus.
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iif a(2,-1) b(3,4)c(-2,3)d(-3,-2) b4 point in plain show that abcd is a rhombus put not a square also find the area of rhombus
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