Prove that a^2b^3 =100 where 2 loga + 3 logb = 2
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Solution:
Given That:
→ 2 ㏒(a) + 3 ㏒(b) = 2
Can be written as:
→ ㏒(a²) + ㏒(b³) = 2
→ ㏒(a²b³) = 2
We know that:
→ ㏒(m) = n or 10ⁿ = m
Similarly:
→ 10² = a²b³
→ a²b³ = 10²
→ a²b³ = 100
Hence Proved...!!
To Know More:
Laws of Logarithms.
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