Math, asked by arshiya1294, 8 months ago

Prove that a, a +3, + 6 cannot be a geometrical sequence.​

Answers

Answered by jaya92001
0

I a G.P r2/r1=r3/r2

r1=a

r2=a+3

r3=6

then a+3/a=6/a+3

So it is not equal

hence the given sequence is not geometric progression

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