Question

prove that (a+b)^-1 (a^-1+b^-1)= 1/ab​

Answer 1

Answer:

hence proved.......,.........

Answer 2

Answer:

$(a+b)^{-1} . (a^{-1} + b^{-1}) = \frac{1}{ab} \\\\\frac{1}{a+b} } .(\frac{1}{a} +\frac{1}{b}) } = \frac{1}{ab} \\\\\frac{1}{a+b} } .(\frac{a+b}{ab} )} = \frac{1}{ab} \\\\\frac{1}{a+b} * \frac{a+b}{ab} = \frac{1}{ab}$

a+b and a+b gets cancelled

$\frac{1}{ab}= \frac{1}{ab}\\\\ LHS=RHS\\\\hence Proved....$