prove that (a – b)2 + 2c (a – b) = (a – b)[ (a – b) + 2c ]
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Answered by
2
hai friend,
L.H.S =R.H.S
then equation is correct
first considering R.H.S
R.H.S
=(a – b)[ (a – b) + 2c ]
multiplying the terms
=(a-b)²+2c(a-b)
which is equal to L.H.S
THUS PROVED, (a – b)2 + 2c (a – b) = (a – b)[ (a – b) + 2c ]
hope helped
L.H.S =R.H.S
then equation is correct
first considering R.H.S
R.H.S
=(a – b)[ (a – b) + 2c ]
multiplying the terms
=(a-b)²+2c(a-b)
which is equal to L.H.S
THUS PROVED, (a – b)2 + 2c (a – b) = (a – b)[ (a – b) + 2c ]
hope helped
Answered by
1
LHS = (a - b)² + 2 c (a - b)
Take (a-b) as a common factor:
LHS = (a-b) [ (a-b) + 2 c ]
= RHS.
This is very simple and direct.
Take (a-b) as a common factor:
LHS = (a-b) [ (a-b) + 2 c ]
= RHS.
This is very simple and direct.
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