Math, asked by ballu5, 1 year ago

prove that (a – b)2 + 2c (a – b) = (a – b)[ (a – b) + 2c ]

Answers

Answered by HappiestWriter012
2
hai friend,
L.H.S =R.H.S
then equation is correct

first considering R.H.S

R.H.S
=(a – b)[ (a – b) + 2c ]
multiplying the terms

=(a-b)²+2c(a-b)

which is equal to L.H.S

THUS PROVED, (a – b)2 + 2c (a – b) = (a – b)[ (a – b) + 2c ]


hope helped
Answered by kvnmurty
1
LHS = (a - b)² + 2 c (a - b) 
Take   (a-b) as a common factor:
 LHS = (a-b)  [ (a-b) + 2 c ]
        = RHS.

This is very simple and direct.
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