Math, asked by kumarmeet398, 19 days ago

Prove that (a – b)³ = a³ – b³ – 3ab(a – b)​

Answers

Answered by sunitaranjan786
7

Answer:

(a-b)³=(a-b)(a-b)(a-b)

[a(a-b)-b(a-b)](a-b)

(a²-ab-ba+b²)(a-b)

(a²-2ab+b²)(a-b)

a(a²-2ab+b²)-b(a²-2ab+b²)

a³-2a²b+ab²-a²b+2ab²-b³

a³-b³-3a²b+3ab²

a³-b³-3ab(a-b)

Step-by-step explanation:

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Answered by raisarkar777
2

Hope this answer helps.

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