Prove that (a – b)³ = a³ – b³ – 3ab(a – b)
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(a-b)³=(a-b)(a-b)(a-b)
[a(a-b)-b(a-b)](a-b)
(a²-ab-ba+b²)(a-b)
(a²-2ab+b²)(a-b)
a(a²-2ab+b²)-b(a²-2ab+b²)
a³-2a²b+ab²-a²b+2ab²-b³
a³-b³-3a²b+3ab²
a³-b³-3ab(a-b)
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