Math, asked by navkaur85, 22 days ago

prove that (a+b+c)power 3-a power 3-b power 3-c power 3=3(a+b) (b+c)(c+a)​

Answers

Answered by hammadKhokhar
0

Step-by-step explanation:

Solution

L. H. S= (a+b+c) ³-a³-b³-c³ =====> (i)

Now, Opening formula of (a+b+c)³

As we know that:

(a+b+c)³ = a³+b³+c³+3(a+b) (b+c) (c+a)

So, putting in (i)

(i) ==> L. H. S= a³+b³+c³+3(a+b) (b+c) (c+a) -a³-b³-c³

Therefore, a³+b³+c³ cancels with -a³-b³-c³

And hence we have in last,

3(a+b) (b+c) (c+a) =R. H. S

That is what we have to proof.

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