Math, asked by antoniolyn, 1 month ago

Prove that a|b iff ac|bc where c is not equal to 0

Answers

Answered by ilinfadey149

0

Answer:...

when 1/bc , 1/ca ,1/ab are in AP...

1/ca - 1/bc = 1/ab - 1/ca...

bc -ca/abc2 = ca - ab / a2 bc...

c(b-a)/ c = a(c-b)/ a...

then it becomes...

b-a = c-b...

i.e 2b = a+c...

therefore a, b,c are in AP...

Step-by-step explanation:...

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