prove that (a + b) to the power minus one into a to the power minus one plus B to the power minus one equal to one by a to the power ab
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( a + b)^(-1) × [ a^(-1) + b^(-1)]
= [1 / (a +b)] × ( 1/a + 1/b)
= [ 1 /(a + b)] × [ ( a + b) / (ab)]
= 1 / ab
= ab^(-1)
= [1 / (a +b)] × ( 1/a + 1/b)
= [ 1 /(a + b)] × [ ( a + b) / (ab)]
= 1 / ab
= ab^(-1)
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