Prove that (A-B) union (B-A) = (A union B)-(A intersection B)
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Use definition:
- A - B = A ∩ B' [ here using ' to indicate complement ]
Then
( A - B ) ∪ ( B - A )
= ( A ∩ B' ) ∪ ( B ∩ A' )
= ( A ∪ B ) ∩ ( A ∪ A' ) ∩ ( B' ∪ B ) ∩ ( B' ∪ A' )
= ( A ∪ B ) ∩ ( B' ∪ A' )
= ( A ∪ B ) ∩ ( A ∩ B )' [ De Morgan's Law ]
= ( A ∪ B ) - ( A ∩ B )
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