Question

Prove that a cyclic parallelogram is a rectangle.
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

In the diagram (refer to the image), let ABCD

be the cyclic parallelogram.

➜For your reference, a cyclic quadrilateral (here parallelogram) are those, whose all vertices touches the circumference of the circle.

angle A = angle C (opposite angles of parallelogram are always equal)

.........(1)

and, ange A+ angle B=180° (opposite angles of a cyclic quadrilateral are always supplementary)

angle A+ angle C=180°......from (1)

2(angle A)=180°

angle A=180°/2

angle A=90°

angle C= angle A=90°

Similarly, angle B= angle C=90°

All angles of the cyclic parallelogram (ABCD) are of 90°. Hence, it is a rectangle.