prove that a cyclic parallelogram is a rectangle ?
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Answer:
Explanation:
Given,
ABCD is a cyclic parallelogram.
To prove,
ABCD is a rectangle.
Proof:
∠1+∠2=180° Opposite angles of a cyclic parallelogram
Also, Opposite angles of a cyclic parallelogram are equal.
Thus,
∠1=∠2
⇒∠1+∠1=180°
⇒∠1=90°
One of the interior angle of the parallelogram is right angled. Thus,
ABCD is a rectangle.
solution
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Answer:
A special quadrilateral with it's properties called " cyclic quadrilateral"
Explanation:
* opposite Angles of a cyclic quadrilateral are supplementary * if a pair of opposite Angles of a quadrilateral is supplementary , then the quadrilateral is cyclic .
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