Question

prove that a diagonal of a parallelogram divides it into two congruent triangle​

Answer 1

Step-by-step explanation:

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Answer 2

ABCD is a parallelogram, diagonals AC and BD intersect at O.

In triangles AOD and COB,

DAO = BCO (alternate interior angles)

AD = CB.

ADO = CBO (alternate interior angles)

AOD COB (ASA)

Hence, AO = CO and OD = OB (c.p.c.t)

Thus, the diagonals of a parallelogram bisect each other.