prove that a diagonal of a parallelogram divides it into two congruent triangle
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90°=90°
diagonal will be common in both
and opposite side of parallelogram are equal
so by rhs congruency criteria the two triangle will be congruent
Step-by-step explanation:
hope u got it
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Step-by-step explanation:
Parallelogram Theorem #1: Each diagonal of a parallelogram divides the parallelogram into two congruent triangles. Parallelogram Theorem #2: The opposite sides of a parallelogram are congruent. ... You can show that alternate interior angles are congruent and hence lines are parallel for this part of the proof.
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