Question

Prove that a diagonal of a parallelogram divides it into two congruent triangles.

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

REF. Image.

consider Δ ABC and Δ ACD

Since the line segments AB+CD are parallel

to each other and AC is a transversal

∠ ACB = ∠ CAD.

AC = AC (common side)

∠CAB = ∠ ACD.

Thus, by ASA criteria

ΔABC ≅ ΔACD

The corresponding part of the congruent

triangle are congruent

AB = CD + AD = BC

Step-by-step explanation:

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