Prove that a pair of opposite sides in a quadrilateral are equal, then it is a parallelogram ?
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Answered by
9
Hola Mate!❤
Below is your answer.
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Given,
In a quadrilateral ABCD,
AB = CD , AD = BC.
To prove,
ABCD is a parallelogram.
Construction,
Join AC.
Proof
Consider ΔABC and ΔCDA
AC = AC (common side)
DA = CB (given)
AB = CD (given)
∴ ΔABC ≅ ΔCDA by SSS congruency.
⇒ ∠DCA = ∠CAB (CPCT).
⇒ ∠CAD = ∠ACB (CPCT)
∴ AB║DC (Since alternate angles ∠DCA and ∠CAB are equal) → 1
∴ DA║CB (Since alternate angles ∠CAD and ∠ACB are equal) → 2
From 1 and 2,
∴ ABCD is a parallelogram as two pairs of opposite sides are parallel.
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Hope It Helps!
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RickHazra99:
Thanks Mate
Answered by
5
Given : ABCD is a quadrilateral
To prove : Oposite sides of quadrilateral ABCD are equal and it is a parallelogram
Construction : Join AC
Proof : In ΔADC & ΔABC,
∠DAC = ∠BCA (pair of alternate interior angles)
∠BAC = ∠ACD (pair of alternate interior angles)
AC = AC (Common)
∴ ΔADC ≅ ΔABC by ASA congruence condition
By CPCT, we can say that
AD = BC and,
AB = DC
∴ ABCD is a parallelogram as its opposite sides are equal
Hope this helps
@PoojaBBSR
To prove : Oposite sides of quadrilateral ABCD are equal and it is a parallelogram
Construction : Join AC
Proof : In ΔADC & ΔABC,
∠DAC = ∠BCA (pair of alternate interior angles)
∠BAC = ∠ACD (pair of alternate interior angles)
AC = AC (Common)
∴ ΔADC ≅ ΔABC by ASA congruence condition
By CPCT, we can say that
AD = BC and,
AB = DC
∴ ABCD is a parallelogram as its opposite sides are equal
Hope this helps
@PoojaBBSR
Attachments:
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