Prove that "A quadrilateral is a parallelogram, if it's one pair of opposite sides are equal and parallel."
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To prove △ABCD is a parallelogram.
Construction : Join AC
PROOF:
In △ABC and CDA, we have
AB = DC
AC = AC
and Angle BAC = Angle DCA
so by SAS congruence rule, we have
△ABC = △CDA
=> Angle BCA = angle DAC
Thus, line ac intersects AB and DC at A and C respectively such that
Angle DAC = Angle BCA
i.e, alternate interior angles are equal.
AD || BC
Thus, AB || CD and AD || BC.
Hence, Quadrilateral ABCD is a parallelogram.
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