Question

Prove that a triangle having sides 5cm, 5cm

$5 \sqrt{2} cm$
is a right angled triangle.
cm, 5cm and​

Answer 1

AB = 5cm ; BC = 5cm ; CA = 5√2cm

In ∆ABC ,

AC² = AB² + BC²

5√2 = √25 + 25

5√2 = √50

5√2 = 5√2

It Obeys Pythagoras Theorem

Thus ∆ABC is a right angled triangle

Hope it helps !!

Vishal ❤

Answer 2

Step-by-step explanation:

By applying pythagoras theorem in it:

${5 \sqrt{2} }^{2} = {5}^{2} + {5}^{2} \\ = 50 = 25 + 25 \\ 50 = 50$

Hence, it is proving pythagoras theorem so one of its angle is right angle.

( By converse of pythagoras theorem )

Hence, it is an right angled triangle.

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