Prove that : (a²- b²)³ + (b²- c²)³ + (c²- a²)³ = 3(a+b)(b+c)(c+a)(a-b)(b-c)(c-a)
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If x+y+z = 0, then we know : x³ + y³ + z³ = 3 x y z
Here x = a² -b² , y = b² - c², z = c² - a²
so LHS: 3 (a²-b²)(b²-c²)(c²-a²)
= 3 (a+b)(a-b)(b+c)(b-c)(c+a)(c-a)
= RHS
Here x = a² -b² , y = b² - c², z = c² - a²
so LHS: 3 (a²-b²)(b²-c²)(c²-a²)
= 3 (a+b)(a-b)(b+c)(b-c)(c+a)(c-a)
= RHS
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