Math, asked by alokraj68699, 1 year ago

Prove that a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ac)

Answers

Answered by Lokeshkorampalli
0
simplification of (a+b+c)(a²+b²+c²-ab-bc-ac) is in the website below.

https://www.symbolab.com/solver/step-by-step/%5Cleft(a%2Bb%2Bc%5Cright)%5Cleft(a²%2Bb²%2Bc²-ab-bc-ac....

so there fore a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ac)
Answered by Shravana1
2
Here's your problem With attachment!!
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