Prove that a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ac)
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simplification of (a+b+c)(a²+b²+c²-ab-bc-ac) is in the website below.
https://www.symbolab.com/solver/step-by-step/%5Cleft(a%2Bb%2Bc%5Cright)%5Cleft(a²%2Bb²%2Bc²-ab-bc-ac....
so there fore a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ac)
https://www.symbolab.com/solver/step-by-step/%5Cleft(a%2Bb%2Bc%5Cright)%5Cleft(a²%2Bb²%2Bc²-ab-bc-ac....
so there fore a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ac)
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